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UCLA surrenders series finale to Sacramento State despite Roch Cholowsky’s two home runs
TL;DR
UCLA Bruins lost 9-6 to Sacramento State in the series finale, despite Roch Cholowsky hitting two home runs. This defeat marked Sacramento State's first win against a No. 1 ranked team.
Key points
- UCLA Bruins lost to Sacramento State 9-6
- Roch Cholowsky hit two home runs
- Sacramento State achieved their first win against a No. 1 ranked team
- UCLA aimed for their 40th victory
- The game was part of a series finale
UCLA BruinsSacramento State HornetsRoch Cholowsky
UCLA infielder, Roch Cholowsky (1) at bat, mid hit during a NCAA baseball game against UC San Diego on February 13, 2026 at Jackie Robinson Stadium in Los Angeles, CA.
(Jessica Cryderman - The Sporting Tribune)
The No. 1 UCLA Bruins dropped the series finale to the Sacramento State Hornets after pitching mishaps in a 9-6 loss on Sunday.
UCLA attempted to gain their 40th victory and 10th straight series sweep over the weekend. Instead, Sacramento State earned their first-ever win against a No. 1 ranked opponent.
Bruins' star shortstop Roch Cholowsky hit two home runs and scored four RBIs in the afternoon, but the Hornets' offensive eruptions were too much to overcome.
UCLA managed to score the first run of the game, the only time they managed to do so over the series. But Sacramento State scored five runs in the third inning, including a two-run home run from third baseman Jakob Poturnak, his second of the weekend.
UCLA's pitching fell apart in the inning with Landon Stump on the mound in his 11th start of the season. He also walked three batters in the third, the most he's given up in a game since his first start of the year against UC San Diego on February 15.
The Bruins started to chop away at the Hornet's lead in the fourth inning with a sacrifice fly out from freshman Aiden Aguayo to score one run. Cholowsky tagged his 16th home run of the season to left field in the next inning to make it a two-run game.
Sacramento State took advantage of UCLA's defensive errors and bullpen miscues in the sixth and seventh innings to provide insurance runs. An error from third baseman Roman Martin allowed Sacramento State's Jace Jeremiah on base, who scored on a sacrifice fly out three at-bats later.
After a leadoff hit by pitch in the next inning, Sacramento State's Ryan Ellis laid down a bunt that was fielded by Cholowsky and thrown away from third to allow a run.
UCLA's Justin Lee entered the game, but allowed two more runs from RBI singles to give Sacramento State a 9-3 lead. This was the largest deficit UCLA had faced in the season.
But hope was not yet lost for the Bruins. Two singles from Kasen Khansarinia and Dean West gave Cholowsky a chance to put UCLA back into the game.
Q&A
What was the final score of the UCLA vs Sacramento State baseball game?
The final score was 9-6 in favor of Sacramento State.
How many home runs did Roch Cholowsky hit in the game?
Roch Cholowsky hit two home runs during the game.
What significance does Sacramento State's win have?
This win is significant as it marks Sacramento State's first-ever victory against a No. 1 ranked opponent.
What was UCLA aiming for in this series finale?
UCLA was aiming for their 40th victory and a 10th straight series sweep.
