Mets $126 million infielder is already 'untradeable' thanks to brutal contract clause

The reasoning for why the Mets would want to trade Bichette is clear, but why is he untradeable? Well, the issue begins with the uncertainty about his two player options that could force the Mets, or an acquiring team, into spending $84 million on Bichette.

Bo Bichette is 'untradeable' due to $84M player options

Bichette is currently signed for $42 million in 2026, and that's looking like a massive overpay on its own.

It's not simply that Bichette has been forced to play a new position and is struggling, which is what many fans were concerned about at the time of the signing. But, it's the one part of his game that should've been good: his offense.

This season, Bichette is hitting .222 with two homers and 16 RBIs in 40 games and 162 at-bats. His .559 OPS is a brutal figure, and one team's likely to have some concerns about it.

MORE: 75% of Mets' infielders named among biggest disappointments in MLB at their positions

Last season, Bichette posted an .840 OPS in 139 games and 582 at-bats. Between his mediocre-at-best defense and this massive regression offensively, there is palpable concern for the Mets.

If they could trade him now amid a disastrous season, they could get out of $42 million in 2027 and 2028. But his struggles likely mean Bichette will invoke his player options and stick around on a deal far more expensive than he'd get in free agency.

This contract clause, Bichette's pair of player options in 2027 and 2028 worth $42 million apiece, is the main reason why Bichette is untradeable this season. It's a brutal situation for the Mets, as they're at risk of getting stuck with Bichette at $84M for two more years.

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